How do you solve #2x^2 + 5x - 3= 0#?

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Answer 1 · 2015-07-12T16:44:07

#color(blue)(x=1/2, x=-3#

#2x^2+5x−3=0#

We can first factorise the expression and then find the solutions.

Factorising by splitting middle term

#2x^2+color(blue)(5x)−3=0#

#2x^2+color(blue)(6x - 1x)−3=0#

#2x(x+3) - 1(x+3)=0#

#(2x-1)(x+3) =0#

Now we can equate the factors with zero to obtain the solutions.
#2x-1 =0, color(blue)(x=1/2#

#x+3 =0, color(blue)(x=-3#