How do you solve $2x^2 + 5x - 3= 0$ ?

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Answer 1 · 2015-07-12T16:44:07

$color(blue)(x=1/2, x=-3$

$2x^2+5x−3=0$

We can first factorise the expression and then find the solutions.

Factorising by splitting middle term

$2x^2+color(blue)(5x)−3=0$

$2x^2+color(blue)(6x - 1x)−3=0$

$2x(x+3) - 1(x+3)=0$

$(2x-1)(x+3) =0$

Now we can equate the factors with zero to obtain the solutions.
$2x-1 =0, color(blue)(x=1/2$

$x+3 =0, color(blue)(x=-3$

How do you solve 2x^2 + 5x - 3= 02x^2 + 5x - 3= 0?