How do you solve $-2x^2-6=0$ graphically?

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Answer 1 · 2018-05-10T13:57:38

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Please read the explanation.

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$color(green)"Step 1:"$

$"Given: "y = -2x^2-6=0$

Create a data table for $y=f(x) = -2x^2-6$

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Plot the points and graph:

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$color(green)"Step 2:"$

Observations:

The graph of this quadratic function shows that there are no real roots (zeros) because the graph does not cross the x-axis.

Such a graph tells us that the roots of the equation are complex numbers, and will appear in the $"form " a + bi.$

Roots that possess this pattern are called complex conjugates or, in general, conjugate pairs).

$"Vertex: Maximum at" (0,-6)$

$"Axis of Symmetry: " x=0$

Hope it helps.

How do you solve -2x^2-6=0 -2x^2-6=0 graphically?