Question

How do you solve `2x^2+7x+9=0`?

Answer 1

`2x^2+7x+9` is of the form `ax^2+bx+c`, with `a=2`, `b=7` and `c=9`.

The discriminant `Delta` is given by the formula:

`Delta = b^2-4ac = 7^2 - (4xx2xx9) = 49 - 72 = -23`

Since `Delta < 0` the quadratic equation has no real roots. It has two distinct complex roots.