How do you solve (2x - 3)^2 = 1? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer ali ergin Apr 19, 2016 x={1,2} Explanation: (2x-3)^2=1 sqrt((2x-3)^2)=sqrt1 2x-3=±1 if +1 2x=1+3 2x=4 x=4/2 x=2 if -1 2x-3=-1 2x=2 x=1 Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve -3x^2+12x+1=0? How do you solve -4x^2+4x=9? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation 81x^2+1=0? How do you solve -4x^2+4000x=0? How do you solve for x in x^2-6x+4=0? How do you solve x^2-6x-16=0 by factoring? How do you solve by factoring and using the principle of zero products x^2 + 7x + 6 = 0? How do you solve x^2=2x? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1325 views around the world You can reuse this answer Creative Commons License