How do you solve $2x^4 - 10x^2 = 0$ ?

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Answer 1 · 2015-10-31T16:04:53

$x = +sqrt 5$
$x = - sqrt 5$

Here,

It is easy to solve for quadratic function but difficult if the power rises up to more than 3,

in this case you let $x^2 = a$
Now replace the value of $x^2$ with $a$

The new equation is,

$2a^2 - 10a$ =0

Take 2 common for both the terms,

2 ( $a^2 - 5a$ ) =0

$a^2 - 5a = 0$

$a^2 = 5a$

Cancel one a ,

SO,

$a = 5$

Now replace this value of a in $x^2$

SO,

$x^2$ = 5
$x = +- sqrt 5$

So, either, $x = +sqrt 5$
or, $x = - sqrt 5$

How do you solve 2x^4 - 10x^2 = 02x^4 - 10x^2 = 0?