How do you solve #|2x + 4| <8#?
1 Answer
Jun 25, 2016
x < 2
x > 6
Explanation:
I2x + 4I < 8
Separate solving into 2 parts:
a. (2x + 4) < 8
2x < 4
x < 2
b. - (2x + 4) < 8
-2x - 4 < 8
-2x < 12
x > 6
Graph:
============ 0 ======= 2-------------------- 6=============
