How do you solve $2 x + 5 = 0$ $2x+5=0$ ?

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Answer 1 · 2017-02-27T14:21:38

See the entire solution process below:

First, subtract $5$ $color(red)(5)$ from each side of the equation to isolate the $x$ $x$ term while keeping the equation balanced:

$2 x + 5 - 5 = 0 - 5$ $2x + 5 - color(red)(5) = 0 - color(red)(5)$

$2 x + 0 = - 5$ $2x + 0 = -5$

$2 x = - 5$ $2x = -5$

Now, divide each side of the equation by $2$ $color(red)(2)$ to solve for $x$ $x$ while keeping the equation balanced:

$\frac{2 x}{2} = - \frac{5}{2}$ $(2x)/color(red)(2) = -5/color(red)(2)$

$(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = -5/2$

$x = -5/2$

How do you solve 2x+5=02x+5=02x+5=0?