How do you solve $|2x - 5 | 6 = 12$ ?

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Answer 1 · 2016-02-21T22:37:01

$x= 7/2 , x = 3/2$

first write as |2x - 5 | = 2 (divide by 6 )

then 2x - 5 = 2 → 2x = 7 → $x = 7/2$

also 2x - 5 = - 2 → 2x = 3 → $x = 3/2$

Answer 2 · 2016-02-22T00:30:05

$x=3/2,7/2$

First, we can divide both sides by $6$ .

$(abs(2x-5)6)/6=12/6$

$abs(2x-5)=2$

This can no be split up into two separate equations because of the absolute value.

Recall that if $2x-5=-2$ , then $abs(2x-5)=2$ still, so we can write and solve the two following equations:

$2x-5=2$

$2x-5=-2$

Solving for each of these gives $x=7/2$ and $x=3/2$ .

How do you solve |2x - 5 | 6 = 12|2x - 5 | 6 = 12?