How do you solve $2x² + 5x = -3$ ?

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Answer 1 · 2016-04-14T09:27:16

The solutions are:
$x = - 1$

$x = - 3/2$

$2x^2 + 5x = -3$

$2x^2 + 5x + 3 = 0$

The equation is of the form $color(blue)(ax^2+bx+c=0$ where:

$a=2, b= 5 , c= 3$

The Discriminant is given by:

$Delta=b^2-4*a*c$

$= (5)^2-(4* 2 * 3 )$

$= 25 - 24 = 1$

The solutions are normally found using the formula
$x=(-b+-sqrtDelta)/(2*a)$

$x = ((-5 +-sqrt(1))/(2*2)) = (-5+-1 )/4$

The solutions are:
$x = (-5+1 )/4 = -4 /4 = - 1$

$x = (-5 - 1 )/4 = -6 /4 = - 3/2$

How do you solve 2x² + 5x = -32x² + 5x = -3?