How do you solve $2 y^{2} + 6 = y^{2}$ $2y^2+6=y^2$ ?

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Answer 1 · 2015-05-23T15:19:55

$y = \sqrt{6} i = i \sqrt{6}$ $y=sqrt(6)i=isqrt6$

Problem: Solve $2 y^{2} + 6 = y^{2}$ $2y^2+6=y^2$ .

Subtract $6$ $6$ from both sides of the equation.

$2 y^{=} y^{2} - 6$ $2y^=y^2-6$

Subtract $y^{2}$ $y^2$ from both sides.

$y^{2} = - 6$ $y^2=-6$

Take the square root of both sides.

$y = \sqrt{- 6}$ $y=sqrt(-6)$ =

$y = \sqrt{6} i = i \sqrt{6}$ $y=sqrt(6)i=isqrt6$

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