How do you solve $2y^2+6=y^2$ ?

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Answer 1 · 2015-05-23T15:19:55

$y=sqrt(6)i=isqrt6$

Problem: Solve $2y^2+6=y^2$ .

Subtract $6$ from both sides of the equation.

$2y^=y^2-6$

Subtract $y^2$ from both sides.

$y^2=-6$

Take the square root of both sides.

$y=sqrt(-6)$ =

$y=sqrt(6)i=isqrt6$

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