How do you solve $2 y = 3 y^{2}$ $2y = 3y^2$ ?

Question

2488 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-01T04:53:48

$y = 0, \frac{3}{2}$ $y=0, 3/2$

Divide both sides by $y :$ $y:$

$(2cancely)/cancely=(3y^((cancel2)1))/cancely$

$3y=2$

$y=2/3$ will be one solution.

$y=0$ is also a solution. Since both sides originally include an instance of $y, y=0$ results in $0=0,$ a valid solution.

How do you solve 2y = 3y^22y=3y22y = 3y^2?