How do you solve 2z^2 - 10z = -12?

1 Answer
Nghi N.
Jul 26, 2016

2 and 3

Explanation:

y = 2z^2 - 10z + 12 = 0
Use the improved quadratic formula in graphic form (Socratic Search)
D = d^2 = b^2 - 4ac = 100 - 96 = 4 --> d = +- 2
There are 2 real roots:
x = -b/(2a) +- d/(2a) = 10/4 +- 2/4
x = 5/2 +- 1/2 = (5 +- 1)/2 =
x1 = 6/2 = 3 and x2 = 4/2 = 2

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