How do you solve $2z^2 - 16z - 1768 = 0$ by completing the square?

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Answer 1 · 2016-04-21T14:39:00

Dividing the given eq by 2
$z^2-2*z*4+4^2-16-884=0$
$=>(z-4)^2=900=30^2$
$: .z=4+30=34 and z=-30+4=-26$

How do you solve 2z^2 - 16z - 1768 = 02z^2 - 16z - 1768 = 0 by completing the square?