How do you solve $2 z^{2} + 20 z = 0$ $2z^2 + 20z = 0$ ?

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Answer 1 · 2017-01-25T14:58:42

See the entire solution process below:

First, factor the left side of the equation:

$2 z (z + 10) = 0$ $2z(z + 10) = 0$

Next solve each term for $0$ $0$ :

Solution 1)

$2 z = 0$ $2z = 0$

$\frac{2 z}{2} = \frac{0}{2}$ $(2z)/color(red)(2) = 0/color(red)(2)$

$(color(red)(cancel(color(black)(2)))z)/cancel(color(red)(2)) = 0$

$z = 0$

Solution 2)

$z + 10 = 0$

$z + 10 - color(red)(10) = 0 - color(red)(10)$

$z + 0 = -10$

$z = -10$

The solution is: $z = 0$ and $z = -10$

How do you solve 2z^2 + 20z = 02z2+20z=02z^2 + 20z = 0?