How do you solve $3^(2a)=3^(-a)$ ?

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Answer 1 · 2016-11-02T09:47:59

$a=0$

$3^(2a)=3^(-a)=1/3^a$

i.e. $3^(2a)xx3^a=1=3^0$

or $3^(2a+a)=3^0$

Hence, $3a=0$ and $a=0/3=0$

How do you solve 3^(2a)=3^(-a)3^(2a)=3^(-a)?