How do you solve $3 | 2 x + 11 | + 2 < 17$ $3|2x+11|+2<17$ ?

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Answer 1 · 2018-05-29T04:19:45

Solution: $x \in - 8 < x < - 3 or x \in (- 8, - 3)$ $x in -8 < x <-3 or x in (-8,-3)$

$3 | 2 x + 11 | + 2 < 17 or 3 | 2 x + 11 | < 15$ $3 |2 x + 11| +2 <17 or 3 |2 x + 11| <15$ or

$| 2 x + 11 | < \frac{15}{3} or | 2 x + 11 | < 5$ $|2 x + 11| <15/3 or |2 x + 11| < 5$

a) $2 x + 11 < 5 or 2 x < 5 - 11$ $2 x + 11 < 5 or 2 x < 5-11$ or

$2 x < - 6 or x < - \frac{6}{2} or x < - 3$ $2 x < - 6 or x < -6/2 or x < -3$ OR

b) $2 x + 11 > - 5 or 2 x > - 5 - 11$ $2 x + 11 > -5 or 2 x > -5-11$ or

$2 x > - 16 or x > - \frac{16}{2} or x > - 8$ $2 x > - 16 or x > -16/2 or x > -8$

Solution: $x \in - 8 < x < - 3 or x \in (- 8, - 3)$ $x in -8 < x <-3 or x in (-8,-3)$ [Ans]

How do you solve 3|2x+11|+2<173|2x+11|+2<17?