How do you solve 3|2x+11|+2<17? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer Binayaka C. May 29, 2018 Solution: x in -8 < x <-3 or x in (-8,-3) Explanation: 3 |2 x + 11| +2 <17 or 3 |2 x + 11| <15 or |2 x + 11| <15/3 or |2 x + 11| < 5 a) 2 x + 11 < 5 or 2 x < 5-11 or 2 x < - 6 or x < -6/2 or x < -3 OR b) 2 x + 11 > -5 or 2 x > -5-11 or 2 x > - 16 or x > -16/2 or x > -8 Solution: x in -8 < x <-3 or x in (-8,-3) [Ans] Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve |a+1|\le 4? How do you solve |-6t+3|+9 \ge 18? How do you graph |7x| \ge 21? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given |\frac{2x}{7}+9 | > frac{5}{7}? How do you solve abs(2x-3)<=4? How do you solve abs(2-x)>abs(x+1)? How do you solve this absolute-value inequality 6abs(2x + 5 )> 66? See all questions in Absolute Value Inequalities Impact of this question 1741 views around the world You can reuse this answer Creative Commons License