How do you solve $3|2y-5|=27$ and find any extraneous solutions?

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Answer 1 · 2016-07-05T09:13:51

$y=7, or, -2$

$3|2y-5|=27 rArr |2y-5|=9 rArr 2y-5=+-9$

Case I $: 2y-5=+9 rArr 2y=14 rArr y=7.$

Case II $: 2y-5=-9 rArr 2y=-4 rArr y=-2$

These values of $y$ satisfy the given eqn. Hence, the soln.

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How do you solve 3|2y-5|=273|2y-5|=27 and find any extraneous solutions?