How do you solve $3.4 e^{2 - 2 n} - 9 = - 4$ $3.4e^(2-2n)-9=-4$ ?

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Answer 1 · 2016-08-21T02:08:23

$n ≅ 0.80717$ $n~=0.80717$

$3.4 e^{2 - 2 n} - 9 = - 4$ $3.4e^(2-2n) -9=-4$

$3.4 e^{2 (1 - n)} = 5$ $3.4e^(2(1-n)) =5$

$e^{2 (1 - n)} = \frac{5}{3.4}$ $e^(2(1-n)) = 5/3.4$

$2 (1 - n) = ln (\frac{5}{3.4})$ $2(1-n) = ln(5/3.4)$

$1 - n ≅ \frac{0.38566}{2}$ $1-n ~= 0.38566/2$

$- n ≅ 0.19283 - 1 = - 0.80717$ $-n~= 0.19283-1 = -0.80717$

$n ≅ 0.80717$ $n~= 0.80717$

How do you solve 3.4e2−2n−9=−43.4e^(2-2n)-9=-4?