How do you solve $3 {(6)}^{2 x - 3} = 648$ $3(6)^(2x-3)=648$ ?

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How do you solve $3 {(6)}^{2 x - 3} = 648$ $3(6)^(2x-3)=648$ ?

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Answer 1 · 2016-09-05T08:05:35

$x = 3$ $x=3$

Explanation:

$3 {(6)}^{2 x - 3} = 648$ $3(6)^(2x-3)=648$
${(6)}^{2 x - 3} = \frac{648}{3} = 216$ $(6)^(2x-3)=648/3=216$
${(6)}^{2 x - 3} = 216 = 6 \times 6 \times 6 = 6^{3}$ $(6)^(2x-3)=216=6xx6xx6=6^3$

$2 x - 3 = 3$ $2x-3=3$
$\Rightarrow x = 3$ $=>x=3$

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How do you solve $3 {(6)}^{2 x - 3} = 648$ $3(6)^(2x-3)=648$ ?

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How do you solve $3 {(6)}^{2 x - 3} = 648$ $3(6)^(2x-3)=648$ ?