Question

How do you solve `-3 ( t + 5 ) + ( 4 t + 2 ) = 8`?

Answer 1

`t=21`

Explanation:

As we know with any math problem, brackets always need to be sorted out first using BIDMAS. So first, we would expand the brackets.

`color(red)(-3)color(green)((t+color(red)(5))+color(green)((4t+color(red)(2))=color(red)(8)`

`color(red)(-3 xx color(green)(t)=color(green)(3t)`

`color(red)(-3 xx 5)=color(red)(-15`

As `color(green)((4tcolor(red)(+2))` cannot be expanded by anything is stays the same.

Removing the brackets:

`color(green)(-3t)color(red)(-15)+color(green)(4t)color(red)(+2)=color(red)(8)`

Collecting like-terms:

`color(green)(-3t+4t=t)`

`color(red)(-15+2=-13`

Plugging back into equation:

`color(green)(t)color(red)(-13)=color(red)(8)`

To get `color(green)(t)` on it's own, we `color(red)(+13)` to get rid of the `color(red)(-13)` as they cancel out. Remember we add `color(red)(13)` to both sides.

`color(red)(8+13=21)`

`therefore` `t=21`