How do you solve $| 3( x + 2) - 4 | = 1$ ?

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Answer 1 · 2016-09-01T14:58:23

$x =-1/3 and -1$

Start by distributing within the absolute value.

$|3x + 6 - 4| = 1$

$|3x + 2| = 1$

Case 1: The absolute value is positive

$3x + 2 = 1$

$3x = -1$

$x = -1/3$

Case 2: The absolute value is negative

$-(3x + 2) = 1$

$-3x - 2 = 1$

$-3x = 3$

$x = -1$

Hopefully this helps!

How do you solve | 3( x + 2) - 4 | = 1| 3( x + 2) - 4 | = 1?