How do you solve $3(x-5)^2 + 8 = 14$ ?

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Answer 1 · 2016-07-07T07:11:29

$x=5+-sqrt2.$

$x~=6.414$ , or, $x~=3.586$

$3(x-5)^2+8=14.$
$:. 3(x-5)^2=14-8=6.$
$:. (x-5)^2=6/3=2.$
$:. (x-5)=+-sqrt2.$
$:. x=5+-sqrt2.$

Taking, $sqrt2=1.414, x~=5+-1.414.$

$:. x~=5+1.414=6.414$ , or, $x~=5-1.414=3.586$

How do you solve 3(x-5)^2 + 8 = 143(x-5)^2 + 8 = 14?