How do you solve #3^(x-7)=27^(2x)#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Gerardina C. Jul 10, 2016 #x=-7/5# Explanation: Since #27=3^3#, you can rewrite: #3^(x-7)=(3^3)^(2x)# #3^(x-7)=3^(6x)# that's #x-7=6x# #5x=-7# #x=-7/5# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 1424 views around the world You can reuse this answer Creative Commons License