How do you solve $30 - 5 (4^{2} - 8 \div 4 - 5 \cdot 2)$ $30-5(4^2-8÷4-5*2)$ ?

Question

How do you solve $30 - 5 (4^{2} - 8 \div 4 - 5 \cdot 2)$ $30-5(4^2-8÷4-5*2)$ ?

1 Answer

Impact of this question

3662 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-28T14:39:47

$10$ $10$

Explanation:

According to B.E.D.M.A.S., simplify the expression within the brackets. Start by simplifying the exponents.

$30 - 5 (4^{2} - 8 \div 4 - 5 \cdot 2)$ $30-5(color(red)(4^2)-8-:4-5*2)$

$= 30 - 5 (16$ $=30-5(color(red)(16)$ $- 8 \div 4 - 5 \cdot 2)$ $color(blue)(-8-:4)-5*2)$

Multiply/divide the numbers from left to right within the brackets.

$= 30 - 5 (16$ $=30-5(16$ $- 2$ $color(blue)(-2)$ $- 5 \cdot 2)$ $color(darkorange)(-5*2))$

$= 30 - 5 (16 - 2$ $=30-5(color(teal)(16-2)$ $- 10)$ $color(darkorange)(-10))$

Subtract the numbers from left to right within the brackets.

$= 30 - 5 (14 - 10)$ $=30-5(color(teal)14-10)$

$= 30$ $=30$ $- 5 (4)$ $color(purple)(-5(4))$

Multiply $- 5$ $-5$ by $4$ $4$ .

$= 30$ $=30$ $- 20$ $color(purple)(-20)$

$= 10$ $=10$

Science

Math

Humanities

... and beyond

How do you solve $30 - 5 (4^{2} - 8 \div 4 - 5 \cdot 2)$ $30-5(4^2-8÷4-5*2)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve 30−5(42−8÷4−5⋅2)30-5(4^2-8÷4-5*2)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve $30 - 5 (4^{2} - 8 \div 4 - 5 \cdot 2)$ $30-5(4^2-8÷4-5*2)$ ?