How do you solve $30 x - 45 = 5 x^{2}$ $30x - 45 =5x^2$ ?

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How do you solve $30 x - 45 = 5 x^{2}$ $30x - 45 =5x^2$ ?

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Answer 1 · 2016-12-10T18:08:52

$x = 3$ $x=3$

Explanation:

$30 x - 45 = 5 x^{2}$ $30x-45=5x^2$
multiply both sides with-1
$+ 30 x + 45 = - 5 x^{2}$ $+30x+45=-5x^2$
$5 x^{2} + 30 x + 45 = 0$ $5x^2+30x+45=0$
$5 (x^{2} + 6 x + 9) = 0$ $5(x^2+6x+9)=0$
$5 (x - 3) (x - 3) = 0$ $5(x-3)(x-3)=0$
multiply both sides by $\frac{1}{x - 3}$ $1/(x-3)$
$5 (x - 3) = 0$ $5(x-3)=0$
$x - 3 = 0$ $x-3=0$
$x = 3$ $x=3$

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How do you solve $30 x - 45 = 5 x^{2}$ $30x - 45 =5x^2$ ?

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How do you solve $30 x - 45 = 5 x^{2}$ $30x - 45 =5x^2$ ?