How do you solve $32=2^(x+4)$ ?

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Answer 1 · 2016-05-20T07:35:19

The solution is $x=1$

To solve such equation we first have to write the number $32$ as a power of $2$ .

$32=2^(x+4)$

$2^5=2^(x+4)$

Now we can change the equation with powers to the equality of exponents.

$5=x+4$

$x=5-4$

$x=1$

How do you solve 32=2^(x+4)32=2^(x+4)?