How do you solve $3e^(-b)=56$ ?

Question

1873 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-21T11:06:37

$b=-2.9268$

As $3e^(-b)=56$ , we have

$3/e^b=56$ or

$3=56e^b$ or

$e^b=3/56$ and taking natural logarithm on both sides

$b=ln3-ln56=1.0986-4.0254=-2.9268$

How do you solve 3e^(-b)=563e^(-b)=56?