How do you solve $3j + 2= 8$ ?

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Answer 1 · 2018-05-02T05:07:28

$j = 2$

$3j + 2 = 8$

To solve for the variable $j$ , we have to make it alone. To do so, first subtract $color(blue)2$ from both sides of the equation:

$3j + 2 quadcolor(blue)(-quad2) = 8 quadcolor(blue)(-quad2)$

$3j = 6$

Now divide both sides by $color(blue)$ :
$(3j)/color(blue)3 = 6/color(blue)3$

So the final answer is
$j = 2$

Hope this helps!

How do you solve 3j + 2= 83j + 2= 8?