How do you solve #3m^2 - 5m = -2#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Daniel L. Jun 23, 2015 This equation has 2 solutions: #m_1=2/3# and #m_2=1# Explanation: #3m^2-5m=-2# #3m^2-5m+2=0# #Delta = (-5)^2-4*3*2=25-24=1# #sqrt(Delta)=1# #m_1=(5-1)/(6)=2/3# #m_2=(5+1)/6=1# Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1448 views around the world You can reuse this answer Creative Commons License