How do you solve $3 m^{2} - 5 m = - 2$ $3m^2 - 5m = -2$ ?

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Answer 1 · 2015-06-23T10:23:10

This equation has 2 solutions: $m_{1} = \frac{2}{3}$ $m_1=2/3$ and $m_{2} = 1$ $m_2=1$

$3 m^{2} - 5 m = - 2$ $3m^2-5m=-2$

$3 m^{2} - 5 m + 2 = 0$ $3m^2-5m+2=0$

$Delta = (-5)^2-4*3*2=25-24=1$

$sqrt(Delta)=1$

$m_1=(5-1)/(6)=2/3$

$m_2=(5+1)/6=1$

How do you solve 3m^2 - 5m = -23m2−5m=−23m^2 - 5m = -2?