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How do you solve $(3n+2)(n-2)=0$ ?

1 Answer

Apr 23, 2017

$n=-2/3$ and $n=2$

Explanation:

$(3n+2)(n-2=0)$

:. $3n+2=0$ and $n-2=0$

$:.3n=-2$ , $n=-2/3$ and $n=2$

$:.n=-2/3$ and $n=2$

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