How do you solve $3p^2 + 17p= -10$ ?

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Answer 1 · 2016-03-18T15:02:52

The solutions are:
$p=-2/3$

$p=-5$

$3p^2 + 17p = -10$

$3p^2 + 17p +10=0$

The equation is of the form $color(blue)(ap^2+bp+c=0$ where:

$a=3, b=17, c=10$

The Discriminant is given by:

$Delta=b^2-4*a*c$

$= (17)^2-(4*3*10)$

$= 289-120= 169$

The solutions are found using the formula
$p=(-b+-sqrtDelta)/(2*a)$

$p = (-17+-sqrt(169))/(2*3) = ((-17 +-13))/6$

$p=(-17 +13)/6 = -cancel4/cancel6 = -2/3$

$p=(-17 -13)/6 = -30/6 = -5$

How do you solve 3p^2 + 17p= -103p^2 + 17p= -10?