How do you solve $3x^2 = 108$ ?

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Answer 1 · 2017-07-07T19:41:42

$x=+-6$

$3x^2 = 108$

$(cancel(3)x^2)/cancel(3) = 108/3$

$x^2 = 36$

$x=sqrt(36)$

$x=+-6$

Answer 2 · 2017-07-07T19:56:07

$x = pm 6$

We have: $3 x^(2) = 108$

First, let's divide both sides of the equation by $3$ :

$Rightarrow frac(3 x^(2))(3) = frac(108)(3)$

$Rightarrow x^(2) = 36$

Then, let's subtract $36$ from both sides:

$Rightarrow x^(2) - 36 = 36 - 36$

$Rightarrow x^(2) - 36 = 0$

The left-hand side of the equation is now in the form of a difference of squares.

We can factorise it in the following way:

$Rightarrow (x + 6)(x - 6) = 0$

Using the null factor law:

$therefore x = pm 6$

Therefore, the solutions to the equation are $x =- 6$ and $x = 6$ .

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