How do you solve $3x^2=12$ ?

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Answer 1 · 2018-03-24T18:14:18

Divide to isolate x and find the square root.

$3x^ = 12$ divide both sides by 3

$3x^2/3 = 12/3$ this gives

$x^2 = 4$ take the square root of both sides

$x = 2, -2$

Answer 2 · 2018-03-24T18:14:19

$x=+-2$

$3x^2=12$

$x^2=4 rarr$ Divide each side by 3

$x=+-2 rarr$ $(-2)^2=2^2=4$

There are two answers: -2 and 2

How do you solve 3x^2=123x^2=12?