How do you solve #3x^2 + 2x - 5 = 0#?

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Answer 1 · 2016-05-07T06:43:10

#(3x + 5) = 0#

#x= - (5/3)#

#x - 1 = 0#
#x= 1#

Hence, solution is #x = -(5/3) or x=1#

The question gives you an equation #3x^2 + 2x -5 = 0#.

Hence to solve the equation, factorise.

#3x^2 + 2x -5 = 0#
#(3x + 5)(x -1) = 0#

The 2 factors of the equation are #(3x + 2) and (x - 1).#

With #(3x + 5) = 0 # and #(x - 1) = 0#
Solve for #x# to find the solutions.