How do you solve $3x^2+ 2x = 8$ by factoring?

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Answer 1 · 2015-08-12T01:39:31

$x=4/3$ and $x=-2$

Subtract $8$ from both sides

$3x^2+2x-8=0$

This will factor into

$(3x-4)(x+2)=0$

So

$3x-4=0$ or $x+2=0$

Solving each of these

$3x=4$

$x=4/3$

$x+2=0$

$x=-2$

How do you solve 3x^2+ 2x = 83x^2+ 2x = 8 by factoring?