How do you solve $3 x^{2} + 3 = 51$ $3x^2 + 3 = 51$ ?

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Answer 1 · 2018-06-18T04:37:02

$x = = 4, - 4$ $color(brown)(x = =4, -4$

$3 x^{2} + 3 = 51$ $3x^2 + 3 = 51$

$3 x^{2} = 51 - 3 = 48$ $3x^2 = 51 - 3 = 48$

$x^{2} = \frac{48}{3} = 16$ $x^2 = 48/3 = 16$

$x = \pm \sqrt{16} = \pm 4$ $color(brown)(x = +- sqrt(16) = +- 4$

How do you solve 3x2+3=513x^2 + 3 = 51?