How do you solve $3x^2+45=24x$ by factoring?

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Answer 1 · 2016-10-26T06:16:58

$x=5$ , $3$

$3x^2+45=24x$

$3x^2-24x+45=0$

Factorise.

$3x^2-9x-15x+45=0$

$3x(x-3)-15(x-3)=0$

$(3x-15)(x-3)=0$

$3x-15=0$ and $x-3=0$

$:.x=15/3=5$ and $x=3$

How do you solve 3x^2+45=24x3x^2+45=24x by factoring?