How do you solve #3x^2 + 4x + 3 = 0# by completing the square?
1 Answer
Sep 10, 2017
#x= +-(isqrt(-5))/3-2/3#
Explanation:
Given -
#3x^2+4x+3=0#
Take the constant term to right
#3x^2+4x=-3#
Divide each term on both sides by the coefficient of
#(3x^2)/3+(4x)/3=(-3)/3#
#x^2+4/3 x=-1#
Divide the coefficient
#x^2+2/3 x+4/9=-1+4/9=(-9+4)/9=-5/9#
#(x+2/3)^2=-5/9#
Take square root on both sides
#(x+2/3)=sqrt(-5/9)=sqrt(-5)/3#
#x= +-(isqrt(-5))/3-2/3#
