How do you solve $3x^2-4x=4$ ?

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Answer 1 · 2015-06-17T04:11:03

$color(green)( x=-2/3 and x=2$

Here, we can first factorise the expression and thereby find the solutions:

Factorising by splitting the middle term
$3x^2-4x -4 = 0$
$3x^2-6x + 2x -4 =0$
$3x(x-2) +2(x-2) = 0$
$color(green)( (3x+2)(x-2) =0$

Equating the factors with zero
$3x +2 = 0 , x = -2/3$
$x-2 = 0 , x=2$

So the solutions are:
$color(green)( x=-2/3 and x=2$

How do you solve 3x^2-4x=43x^2-4x=4?