How do you solve $3x^2 +6 =11x$ ?

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Answer 1 · 2016-05-04T17:36:39

The solutions are:

$x= 3 , x = 2/3$

$3x^2 + 6 = 11x$

$3x^2 - 11x + 6 =0$

The equation is of the form $color(blue)(ax^2+bx+c=0$ where:
$a=3, b=-11, c=6$

The Discriminant is given by:

$Delta=b^2-4*a*c$

$= (-11)^2-(4 * 3 * 6 )$

$= 121 - 72=49$

The solutions are normally found using the formula
$x=(-b+-sqrtDelta)/(2*a)$

$x = (-(-11)+-sqrt(49))/(2*3) = ((11+-7))/6$

$x = (11 +7) / 6 = 18/6 = 3$

$x = (11 -7) / 6 = 4/6 = 2/3$

How do you solve 3x^2 +6 =11x 3x^2 +6 =11x?