How do you solve $3x^2+6x+3=0$ ?

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Answer 1 · 2016-04-02T17:29:11

The solution is: $color(blue)(x= -1$

$3x^2 + 6x + 3 = 0$

The equation is of the form $color(blue)(ax^2+bx+c=0$ where:
$a=3, b=6, c=3$

The Discriminant is given by:

$Delta=b^2-4*a*c$

$= (6)^2-(4* 3 * 3)$

$= 36 - 36 = 0$

The solutions are found using the formula
$x=(-b+-sqrtDelta)/(2*a)$

$x=(-6+-sqrt0)/(2*3)$

$x=(-6+- 0)/( 6)$

$x=-6/6$

$color(blue)(x= -1$

How do you solve 3x^2+6x+3=03x^2+6x+3=0?