How do you solve $-3x^2 - x + 2 = 0$ ?

Question

12853 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-06T02:53:13

$x = -1, 2/3$

$-3x^2-x+2=0$

$(−3x+2)(x+1) = 0$

Solving for the first solution

$-3x+2=0$

$-3x = -2$

$x = 2/3$

Solving for the second solution

$x+1 = 0$

$x = -1$

How do you solve -3x^2 - x + 2 = 0-3x^2 - x + 2 = 0?