Question

How do you solve `3x² = 2x +4`?

Answer 1

First, rewrite it as `3x^2-2x-4=0`, then use the quadratic formula and you find the roots to be `x=(1+-sqrt13)/3`

Explanation:

Once you have it in the form `3x^2-2x-4=0`, the quadratic formula gives a reliable means of finding the roots:

`x=(2+- sqrt((-2)^2-4(3)(-4)))/(2(3))=(2+-sqrt52)/6=(2+-2sqrt13)/6`

Now, just divide each term by 2:

`x=(1+-sqrt13)/3`