How do you solve $3 x + 5 \geq y$ $3x + 5 ≥ y$ ?

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Answer 1 · 2015-09-24T20:56:18

Refer to explanation

You need to find all the points $(x, y)$ $(x,y)$ in a cartesian plane for which

$3 x + 5 \geq y$ $3x+5>=y$ .

A graphical solution is

enter image source here

The shaded area is all the points that satisfy the inequality.

How do you solve 3x + 5 ≥ y 3x+5≥y3x + 5 ≥ y ?