How do you solve $3x-5y+2z=-13$ , $x+4y-2z=8$ and $-3x+5y-2z=3$ ?

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Answer 1 · 2015-02-13T20:05:37

There are no solutions to this set of equations.

equation 1: $3x−5y+2z=−13$
equation 2: $x+4y−2z=8$
equation 3: $−3x+5y−2z=3$

Adding equation 1 and equation 3, we get
$0*x + 0*y + 0*z = -10$
or
$0 = -10$
(which is impossible)

How do you solve 3x-5y+2z=-133x-5y+2z=-13, x+4y-2z=8x+4y-2z=8 and -3x+5y-2z=3-3x+5y-2z=3?