How do you solve $3x + 6 > 36$ and $3x + 6<=54$ ?

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Answer 1 · 2015-06-25T22:45:18

You may always add and subtract on both sides. You may also multiply or divide by a positive number, also on both sides.

$3x+6>36->$ subtract $6$
$3x>30->x>10$

$3x+6<=54->$
$3x<=48->x<=16$

Combining: $10 < x<=16$

How do you solve 3x + 6 > 363x + 6 > 36 and 3x + 6<=543x + 6<=54?