How do you solve $4 (3 x + 5) - 2 (2 - 4 x) = 6 - 2 x$ $4(3x+5)-2(2-4x)=6-2x$ ?

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How do you solve $4 (3 x + 5) - 2 (2 - 4 x) = 6 - 2 x$ $4(3x+5)-2(2-4x)=6-2x$ ?

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Answer 1 · 2018-06-24T08:09:54

$x = - \frac{5}{11}$ $x=-5/11$

Explanation:

$distribute and simplify left side of equation$ $"distribute and simplify left side of equation"$

$12 x + 20 - 4 + 8 x = 6 - 2 x$ $12x+20-4+8x=6-2x$

$20 x + 16 = 6 - 2 x$ $20x+16=6-2x$

$add 2 x to both sides$ $"add "2x" to both sides"$

$22 x + 16 = 6$ $22x+16=6$

$subtract 16 from both sides$ $"subtract 16 from both sides"$

$22 x = 6 - 16 = - 10$ $22x=6-16=-10$

$divide both sides by 22$ $"divide both sides by 22"$

$x = - \frac{10}{22} = - \frac{5}{11}$ $x=-10/22=-5/11$

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How do you solve $4 (3 x + 5) - 2 (2 - 4 x) = 6 - 2 x$ $4(3x+5)-2(2-4x)=6-2x$ ?

1 Answer

Explanation:

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How do you solve 4(3x+5)−2(2−4x)=6−2x4(3x+5)-2(2-4x)=6-2x?

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Explanation:

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How do you solve $4 (3 x + 5) - 2 (2 - 4 x) = 6 - 2 x$ $4(3x+5)-2(2-4x)=6-2x$ ?