How do you solve 4.5>=e^(0.031t)?

1 Answer
Nov 1, 2016

=> t<=ln(4.5)/0.031

=> t<=48.52 to 2 decimal places

Explanation:

As soon as you see the word solve it indicates you need to find at least 1 value.

Note that e is a predefined constant. So the only unknown is t

Also for all ainRR: log_a(a)=1 and we can use this to 'get rid' of e
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Given:" "4.5>=e^(0.031t)

Take logs of both sides

ln(4.5)>=0.031t ln(e)

But ln(e)->log_e(e) =1 giving

ln(4.5) >=0.031t

=> t<=ln(4.5)/0.031

Tony B