How do you solve $4 - (- h) = 68$ $4-(-h)=68$ ?

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How do you solve $4 - (- h) = 68$ $4-(-h)=68$ ?

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Answer 1 · 2017-01-15T16:55:08

$h = 64$ $h = 64$

Explanation:

$- (- h) = h$ $- (-h) = h$

$h = 68 - 4$ $h = 68 - 4$

$h = 64$ $h = 64$

Answer 2 · 2017-01-15T16:56:35

$h = 64$ $h=64$

Explanation:

$4 - (- h) = 68$ $4-(-h)=68$

subtracting a negative quantity is $equivalent to adding the quantity$ $color(blue)"equivalent to adding the quantity"$

$\Rightarrow 4 + h = 68$ $rArr4+h=68$

To solve for h, subtract 4 from both sides of the equation.

$cancel(4)cancel(-4)+h=68-4$

$rArrh=64" is the solution"$

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How do you solve $4 - (- h) = 68$ $4-(-h)=68$ ?

2 Answers

Explanation:

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