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How do you solve $4 (r + 1) = 6 - 2 (1 - 2 r)$ $4(r+1)=6-2(1-2r)$ ?

1 Answer

Aug 31, 2017

The given equation is true for all values of $r$ $r$

Explanation:

$4 (r + 1)$ $4(r+1)$
$XXX = 4 r + 4$ $color(white)("XXX")=4r+4$

$6 - 2 (1 - 2 r)$ $6-2(1-2r)$
$XXX = 6 - (2 - 4 r)$ $color(white)("XXX")=6-(2-4r)$

$XXX = 6 - 2 + 4 r$ $color(white)("XXX")=6-2+4r$

$XXX = 4 + 4 r$ $color(white)("XXX")=4+4r$

So if
$XXX 4 (r + 1) = 6 - 2 (1 - 2 r)$ $color(white)("XXX")4(r+1)=6-2(1-2r)$
then
$XXX 4 r + 4 = 4 + 4 r$ $color(white)("XXX")4r+4=4+4r$

...but this is true for any value of $r$ $r$

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