Question

How do you solve `4(r+1)=6-2(1-2r)`?

Answer 1

The given equation is true for all values of `r`

Explanation:

`4(r+1)`
`color(white)("XXX")=4r+4`

`6-2(1-2r)`
`color(white)("XXX")=6-(2-4r)`

`color(white)("XXX")=6-2+4r`

`color(white)("XXX")=4+4r`

So if
`color(white)("XXX")4(r+1)=6-2(1-2r)`
then
`color(white)("XXX")4r+4=4+4r`

...but this is true for any value of `r`